If the secondary has more turns than the primary, the secondary voltage will be __________ than the primary.

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Multiple Choice

If the secondary has more turns than the primary, the secondary voltage will be __________ than the primary.

Explanation:
Voltage on a winding scales with the turns ratio. In an ideal transformer, Vs = Vp × (Ns / Np). So when the secondary has more turns than the primary, Ns / Np is greater than 1 and the secondary voltage becomes higher than the primary. This is why such a transformer is called a step-up transformer. Power balance (ignoring losses) also means the secondary current is lower than the primary by the same ratio: Is = Ip × (Np / Ns). Real transformers have losses, but the basic turns-to-voltage relationship still governs the result.

Voltage on a winding scales with the turns ratio. In an ideal transformer, Vs = Vp × (Ns / Np). So when the secondary has more turns than the primary, Ns / Np is greater than 1 and the secondary voltage becomes higher than the primary. This is why such a transformer is called a step-up transformer. Power balance (ignoring losses) also means the secondary current is lower than the primary by the same ratio: Is = Ip × (Np / Ns). Real transformers have losses, but the basic turns-to-voltage relationship still governs the result.

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